Advertisements
Advertisements
प्रश्न
Diagram is given below shows velocity – time graph of car P and Q, starting from the same place and in the same direction. Calculate which car is ahead after 10 s and by how much?
उत्तर
Distance covered by car P = area of ΔOAB
= `1/2xx"OB"xx"AB"`
= `1/2xx10xx35`
= 175 m
Distance covered by car Q = area of ΔCDE + area of rectangle DFBE
= `1/2xx"CE"xx"DE"+"EB"xx"BF"`
= `1/2xx(5-2)xx25+(10-5)xx25`
= `75/2+125`
= 37.5 + 125
= 162.5 m
So, car P is a head of car Q by (175 − 162.5) m
i.e. by 12.5 m
APPEARS IN
संबंधित प्रश्न
What conclusion can you draw about the acceleration of a body from the speed-time graph shown below .
Given alongside is the velocity-time graph for a moving body :
Find :
(i) Velocity of the body at point C.
(ii) Acceleration acting on the body between A and B.
(iii) Acceleration acting on the body between B and C.
A body is moving uniformly in a straight line with a velocity of 5 m/s. Find graphically the distance covered by it in 5 seconds.
What type of motion is represented by the following graph ?
Draw a displacement-time graph for a boy going to school with uniform velocity.
Draw a velocity-time graph for the free fall of a body under gravity starting from rest. Take g = 10m s-2
Multiple choice Question. Select the correct option.
In the velocity-time graph, the acceleration is
Represent the position of a body described as at 15 m, 30o north of west, on a graph paper.
The area of the right triangle under a speed-time graph is 500 m, in a time interval of 20 s. What is the speed of the body? Is the motion uniform or non-uniform?
Draw velocity-time graph to show:
Zero acceleration
Write a sentence to explain the shape of graph.
