Question

Differentiate the following:
y = ${\displaystyle {\text{e}}^{x\cos x}}$

Answer 1

y = ${\displaystyle {\text{e}}^{x\cos x}}$

${\displaystyle \frac{\text{d}y}{\text{d}x}={\text{e}}^{x\cos x}(x-\sin x+\cos x\cdot 1)}$

${\displaystyle \frac{\text{d}y}{\text{d}x}={\text{e}}^{x\cos x}(\cos x-x\sin x)}$