Find the derivatives of the following functions with respect to corresponding independent variables: y = tanx-1secx - Mathematics

Find the derivatives of the following functions with respect to corresponding independent variables:

y = `(tanx - 1)/secx`

योग

y = `(tanx - 1)/secx`

`("d"y)/("d"x) = (secx(sec^2x - 0) - (tan x - )secx tanx)/(sec x)^2`

`("d"y)/("d"x) = (secx[sec^2x - (tan x - 1) tanx])/(sec^2x)`

= `([sec^3x - tan^2xx + tanx])/secx`

= `((1 + tanx))/secx`

= `cos x (1 + sinx/cosx)`

`("d"y)/("d"x)` = cos x + sin x

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Differentiation Rules

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अध्याय 10: Differential Calculus - Differentiability and Methods of Differentiation - Exercise 10.2 [पृष्ठ १६०]

अध्याय 10 Differential Calculus - Differentiability and Methods of Differentiation
Exercise 10.2 | Q 11 | पृष्ठ १६०

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