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Draw any angle with vertex O. Take a point A on one of its arms and B on another such that OA = OB. Draw the perpendicular bisectors of OAOA¯ and OBOB¯. Let them meet at P. Is PA = PB ? - Mathematics

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प्रश्न

Draw any angle with vertex O. Take a point A on one of its arms and B on another such that OA = OB. Draw the perpendicular bisectors of `overline"OA"` and `overline"OB"`. Let them meet at P. Is PA = PB ?

संक्षेप में उत्तर
आकृति

उत्तर

  1. Draw any angle whose vertex is O.
  2. With a convenient radius, draw arcs on both rays of this angle while taking O as centre. Let these points be A and B.
  3. Taking O and A as centres and with radius more than half of OA, draw arcs on both sides of OA. Let these be intersecting at C and D. Join CD.
  4. Similarly, we can find the perpendicular bisector `overline"EF"` of `overline"OB"`. These perpendicular bisectors `overline"CD"` and `overline"EF"` will intersect each other at P.

    Now, PA and PB can be measured. These are equal in length.

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अध्याय 14: Practical Geometry - Exercise 14.5 [पृष्ठ २८६]

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एनसीईआरटी Mathematics [English] Class 6
अध्याय 14 Practical Geometry
Exercise 14.5 | Q 9. | पृष्ठ २८६

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