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प्रश्न
Draw the graph of the equation given below. Also, find the coordinates of the point
where the graph cuts the coordinate axes : 6x − 3y = 12
उत्तर
we have
6x − 3y = 12
⇒ 3 (2x - y ) = 12
⇒ 2x - y = 4
⇒ 2x - 4 = y
⇒ y = 2x - 4 ................ (1)
Putting x = 0 in (1) , we get y =- 4
Putting x = 2 in (1) , we get y = 0
Thus, we obtain the following table giving coordinates of two points on the line
represented by the equation 6x - 3y = 12
APPEARS IN
संबंधित प्रश्न
From the choices given below, choose the equation whose graphs are given in the given figures.
For the first figure
(i) y = x
(ii) x + y = 0
(iii) y = 2x
(iv) 2 + 3y = 7x
For the second figure
(i) y = x +2
(ii) y = x − 2
(iii) y = − x + 2
(iv) x + 2y = 6
Draw the graph of the following linear equation in two variable : `(x-2)/3 = y - 3`
Draw the graph of the following linear equations in two variable : 2𝑦 = −𝑥 + 1
Draw the graph for the equation, given below :
2x + 3y = 0
Draw the graph for the equation given below; hence find the co-ordinates of the points where the graph is drawn meets the co-ordinates axes:
`(2x + 15)/(3) = y - 1`
Use graph paper for this question. Take 2 cm = 1 unit on both the axes.
- Draw the graphs of x + y + 3 = 0 and 3x - 2y + 4 = 0. Plot only three points per line.
- Write down the coordinates of the point of intersection of the lines.
- Measure and record the distance of the point of intersection of the lines from the origin in cm.
Draw the graph for each of the following equation: Also, find the coordinates of the points where the graph of the equation meets the coordinate axes:
`(3x + 14)/(2) = (y - 10)/(5)`
Draw the graph for the following
3x + 2y = 14
Draw the graph of y = – 3x
The following observed values of x and y are thought to satisfy a linear equation. Write the linear equation:
| x | 6 | – 6 |
| y | –2 | 6 |
Draw the graph using the values of x, y as given in the above table. At what points the graph of the linear equation
- cuts the x-axis
- cuts the y-axis
