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प्रश्न
Draw the graph of the following linear equation in two variable : `(x-2)/3 = y - 3`
उत्तर
We have
`(x-2)/3 = y - 3`
⇒ ` x - 2 = 3 (y -3) `
⇒ ` x - 2 = 3y - 9 `
⇒ ` x = 3y - 9 + 2`
⇒ `x = 3y - 7`
Putting y = 0 , we get x - 0 = -7 ⇒ x = - 7
Putting y = 2 , we get x - 3 (2) = - 7 ⇒ x =-1
Putting y = 3 , we get x = 3 ( 3) - 7 ⇒ x = 2
Thus, we get the following table giving the two points on the line represented by the
equation `(x -2)/y ` = y - 3
Graph for the equation `(x -2)/y ` = y - 3
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