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प्रश्न
Draw a triangle ABC with BC = 6 cm, AB = 5 cm and ∠ABC = 60°. Then construct a triangle whose sides are `3/4` of the corresponding sides of the ∆ABC.
उत्तर
A ΔA'BC' whose sides are `3/4`of the corresponding sides of ΔABC can be drawn as follows:
Step 1
Draw a ΔABC with side BC = 6 cm, AB = 5 cm and ∠ABC = 60°
Step 2
Draw a ray BX making an acute angle with BC on the opposite side of vertex A.
Step 3
Locate 4 points (as 4 is greater in 3 and 4), B1, B2, B3, B4, on line segment BX.
Step 4
Join B4C and draw a line through B3, parallel to B4C intersecting BC at C'
Step 5
Draw a line through C' parallel to AC intersecting AB at A'. ΔA'BC' is the required triangle.
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