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प्रश्न
Construct an isosceles triangle whose base is 8 cm and altitude 4 cm and then another triangle whose sides are 3/2 times the corresponding sides of the isosceles triangle.
उत्तर
Steps to construct
1. Draw a line segment BC of 8 cm
2. Take a mid point D of BC
3. At D, draw an angler of 90°
4.With centre D,Radius 4cm, draw an arc which intersect line of angle at A
5. Join AB and AC
6. At B, draw an angle CBX of any measure
7. Starting from B, cut there equal parts on BX such that BX1 = X1X2 = X2X3
8. Join X2C
9. Through X3, Draw X3Q || X2C
10. Through Q, Draw QP || CA
∴ ΔPBQ ∼ ΔABC
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संबंधित प्रश्न
Draw a line segment of length 7 cm and divide it internally in the ratio 2 : 3.
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If the point P (6, 7) divides the segment joining A(8, 9) and B(1, 2) in some ratio, find that ratio
Solution:
Point P divides segment AB in the ratio m: n.
A(8, 9) = (x1, y1), B(1, 2 ) = (x2, y2) and P(6, 7) = (x, y)
Using Section formula of internal division,
∴ 7 = `("m"(square) - "n"(9))/("m" + "n")`
∴ 7m + 7n = `square` + 9n
∴ 7m – `square` = 9n – `square`
∴ `square` = 2n
∴ `"m"/"n" = square`
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