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प्रश्न
Estimate the median, the lower quartile and the upper quartile of the following frequency distribution by drawing an ogive:
Marks(more than) | 90 | 80 | 70 | 60 | 50 | 40 | 30 | 20 | 10 | 0 |
No. of students | 6 | 13 | 22 | 34 | 48 | 60 | 70 | 78 | 80 | 80 |
उत्तर
Given data is cumulative data , so draw the ogive as it is .
Marks (more than) | No. of students (f) |
0 | 80 |
10 | 80 |
20 | 78 |
30 | 70 |
40 | 60 |
50 | 48 |
60 | 34 |
70 | 22 |
80 | 13 |
90 | 6 |
Take a graph paper and draw both the axes.
On the x-axis , take a scale of 1 cm = 10 to represent the marks (more than).
On the y - axis , take a scale of 1cm = 10 to represent the no. of students.
Now, plot the points (0,80) , (10,80) , (20,78) , (30,70) , (40,60) , (50,48) , (60,34) , (70,22) ,(80,13) , (90,6).
Join them by a smooth curve to get the ogive.
No. of terms = 80
∴ Median = `(40 + 41)/2` = 40.5th term
Through mark of 40.5 on y-axis draw a line parallel to x-axis which meets the curve at A. From A, draw a perpendicular to x-axis which meets it at B.
The value of B is the median which is 55.
Lower Quartile (Q1) = `n/4 = 80/4` = 20th term
Through mark of 20 on y-axis draw a line parallel to x-axis which meets the curve at P. From P , draw a perpendicular to x-axis which meets it at Q.
The value of Q is the lower quartile which is 71.
Upper Quartile (Q3) = `(n xx 3)/4 = (80 xx 3)/4` = 60th term
Through mark of 60 on y-axis draw a line parallel to x-axis which meets the curve at R. From R, draw a perpendicular to x-axis which meets it at S.
The value of S is the upper Quartile which is 40.
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