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Evaluate: tan (55° – A) – cot (35° + A) - Mathematics

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प्रश्न

Evaluate:

tan (55° – A) – cot (35° + A)

मूल्यांकन

उत्तर

tan (55° – A) – cot (35° + A)

= tan [90° – (35° + A)] – cot (35° + A)

= cot (35° + A) – cot (35° + A)

= 0

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Complimentary Angles for Tangent ( Tan ) and Contangency ( Cot )
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 25: Complementary Angles - Exercise 25 [पृष्ठ ३१०]

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सेलिना Concise Mathematics [English] Class 9 ICSE
अध्याय 25 Complementary Angles
Exercise 25 | Q 6.4 | पृष्ठ ३१०
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