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Evaluate: tan (55° – A) – cot (35° + A) - Mathematics

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Question

Evaluate:

tan (55° – A) – cot (35° + A)

Evaluate

Solution

tan (55° – A) – cot (35° + A)

= tan [90° – (35° + A)] – cot (35° + A)

= cot (35° + A) – cot (35° + A)

= 0

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Complimentary Angles for Tangent ( Tan ) and Contangency ( Cot )
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Q 6.4
Chapter 25: Complementary Angles - Exercise 25 [Page 310]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 25 Complementary Angles
Exercise 25 | Q 6.4 | Page 310

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