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Show That: Tan 10° Tan 15° Tan 75° Tan 80° = 1 - Mathematics

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Question

Show that: tan 10° tan 15° tan 75° tan 80° = 1.

Sum

Solution

L.H.S.
= tan 10° tan 15° tan 75° tan 80°
= tan (90° - 80°) tan (90° - 75°) tan 75° tan 80°
= cot 80° cot 75 ° tan 75° tan 80°
= (cot 80° tan 80°)(cot 75° tan 75°)
= (1)(1)
= 1
= R.H.S.

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Complimentary Angles for Tangent ( Tan ) and Contangency ( Cot )
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Chapter 25: Complementary Angles - Exercise 25 [Page 310]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 25 Complementary Angles
Exercise 25 | Q 3.1 | Page 310
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