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Evaluate: Cot 54 ° Tan 36 ° + Tan 20 ° Cot 70 ° − 2 - Mathematics

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Question

Evaluate: `(cot54°)/(tan36°) + (tan20°)/(cot70°)-2`

Sum

Solution

`(cot54°)/(tan36°) + (tan20°)/(cot70°)-2`

= `cot(90° - 36°)/(tan 36°)+ tan(90° - 70°)/(cot 70°) - 2`

= `(tan 36°)/(tan 36°) + (cot 70°)/(cot 70°)-2`
= 1 + 1 - 2
= 2 - 2
= 0

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Complimentary Angles for Tangent ( Tan ) and Contangency ( Cot )
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Chapter 25: Complementary Angles - Exercise 25 [Page 310]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 25 Complementary Angles
Exercise 25 | Q 2.3 | Page 310
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