Advertisements
Advertisements
प्रश्न
Evaluate the following, using suitable identity
1032
योग
उत्तर
1032 = (100 + 3)2
Taking a = 100 and b = 3
(a + b)2 = a2 + 2ab + b2 becomes
(100 + 3)2 = 1002 + 2(100)(3) + 32
= 10000 + 600 + 9
1032 = 10609
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Algebra - Exercise 3.1 [पृष्ठ ६२]
APPEARS IN
संबंधित प्रश्न
Find the following squares by suing the identities.
(6x2 − 5y)2
Simplify (ab + bc)2 − 2ab2c
Using identities, evaluate 9982
Expand `("a"/2+"b"/3)^2`
Expand `("x"+1/2)^2`
Expand the following square, using suitable identities
(2x + 5)2
Factorise the following using suitable identity
a2 + 6ab + 9b2 – c2
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
4x2 + 4x + 1
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
a2x2 + 2abxy + b2y2
If p + q = 12 and pq = 22, then find p2 + q2.
