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प्रश्न
Explain the following:
The surrounding become pleasantly warm when water in a lake starts freezing in cold countries.
उत्तर
The reason is that the specific latent heat of fusion of ice is sufficiently high, so when the water of lake freezes, a large quantity of heat has to be released and hence the surrounding temperature becomes pleasantly warm.
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संबंधित प्रश्न
What do you understand by the term latent heat?
Which has more heat: 1 g ice at 0℃ or 1g water 0℃? Give reason.
- Which requires more heat: 1 g ice at 0℃ or 1 g water at 0℃ to raise its temperature to 10℃?
- Explain your answer in part (a).
Explain the following:
The heat supplied to a substance during it change of state, does not cause any rise in its temperature.
The specific latent heat of fusion of water is ______.
Calculate the total amount of heat energy required to convert 100 g of ice at −10℃ completely into water at 100℃. Specific heat capacity of ice = 2.1 J g-1 K-1, specific heat capacity of water = 4.2 J g-1K-1, specific latent heat of ice = 336 J g-1.
Explain the following temperature vs time graph.
Answer the following:
Explain the role of latent heat in the change of state of a substance.
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What observation you will record and how will you determine the specific latent heat of fusion of ice?
Steam at 100°C is passed over 1000 g of ice at 0°C. After some time, 600 g of ice at 0°C is left and 450 g of water at 0°C is formed. Calculate the specific latent heat of vaporization of steam (Given: specific heat capacity of water = 4200 J/kg°C, specific latent heat of fusion of ice = 336,000 J/kg.)
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1 kg of dry air at a temperature of 40 °C can hold a maximum of 49 g of water vapour.
Write scientific reason.
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Define specific latent heat capacity
600 g of copper at 50°C is mixed with lOOOg water at 20°C. Find the final temperature of the mixture. The specific heat capacity of copper is 0.4 Jg-1°C-1 and that of water is 4.2 Jg-1°C-1
2875 J of heat is required to melt 115 g of lead at its melting point. Calculate the specific latent heat capacity of fusion of lead.
20 g of ice at 0°C absorbs 10,920 J of heat energy to melt and change to water at 50°C. Calculate the specific latent heat of fusion of ice. Specific heat capacity of water is 4200 J kg-1 K-1.
