Advertisements
Advertisements
प्रश्न
f(x) = 2x3 − 9x2 + x + 12, g(x) = 3 − 2x
उत्तर
It is given that f(x) = 2x3 − 9x2 + x + 12 and g(x) = (3 − 2x)
By factor theorem, (3 − 2x) is the factor of f(x), if f(3/2)= 0
Therefore,
In order to prove that (3 − 2x) is a factor of f(x). It is sufficient to show that `f(3/2) = 0`
Now,
`f(3/2) = 2(3/2)^3 -9(3/2)^2 +(3/2) + 12`
` = 27/4 - 81/4 + 3/2 + 12`
` = 54 / 4 + 3/2 + 12`
` = -27/2 + 3/2 +12`
` = -12 + 12`
`= 0`
Hence, (3 − 2x), is the factor of polynomial f(x).
APPEARS IN
संबंधित प्रश्न
Identify polynomials in the following:
`f(x)=2+3/x+4x`
Show that (x + 4) , (x − 3) and (x − 7) are factors of x3 − 6x2 − 19x + 84
For what value of a is (x − 5) a factor of x3 − 3x2 + ax − 10?
If x − 2 is a factor of the following two polynomials, find the values of a in each case x5 − 3x4 − ax3 + 3ax2 + 2ax + 4.
x4 − 2x3 − 7x2 + 8x + 12
If x140 + 2x151 + k is divisible by x + 1, then the value of k is
If x + a is a factor of x4 − a2x2 + 3x − 6a, then a =
The value of k for which x − 1 is a factor of 4x3 + 3x2 − 4x + k, is
Factorise the following:
`sqrt(5)"a"^2 + 2"a" - 3sqrt(5)`
Factorise:
2x3 – 3x2 – 17x + 30