Advertisements
Advertisements
प्रश्न
Factorise : 16p4 – 1
उत्तर
16p4 – 1 = 24p4 – 1
= (22)2(p2)2 – 12
= (22p2)2 – 12
Comparing with a2 – b2 (a + b)(a – b) where a = 22p2 and b = 1
∴ (22p2)2 – 12 = (22p2 + 1)(22p2 – 1)
= (4p2 + 1)(4p2 – 1)
∴ 16p4 – 1 = (4p2 + 1)(4p2 – 1)
= (4p2 + 1)(22p2 – 12)
= (4p2 + 1)[(2p)2 – 12]
= (4p2 + 1)(2p + 1)(2p – 1) ...[∵ using a2 – b2 = (a + b)(a – b)]
∴ 16p4 – 1 = (4p2 + 1)(2p + 1)(2p – 1)
APPEARS IN
संबंधित प्रश्न
The product of (x + 5) and (x – 5) is ____________
Factorise the following algebraic expression by using the identity a2 – b2 = (a + b)(a – b)
9 – 4y2
Find the value of (x – y)(x + y)(x2 + y2)
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`(2p^2)/25 - 32q^2`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`x^2/25 - 625`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
x4 – y4
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
x4 – y4 + x2 – y2
Factorise the expressions and divide them as directed:
(x4 – 16) ÷ x3 + 2x2 + 4x + 8
Verify the following:
(ab + bc)(ab – bc) + (bc + ca)(bc – ca) + (ca + ab)(ca – ab) = 0
Verify the following:
(p – q)(p2 + pq + q2) = p3 – q3
