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प्रश्न
Factorise : a6 - b6
योग
उत्तर
We know that,
a3 + b3 = ( a + b )( a2 - ab + b2 ) ....(1)
a3 - b3 = ( a - b )( a2 + ab + b2 ) ....(2)
a6 - b6
= ( a3)2 - (b3)2
= ( a3 + b3 )( a3 - b3 )
= ( a + b )( a2 - ab + b2 )( a - b )( a2 + ab + b2 )
[ From(1) and (2) ]
= ( a + b )( a - b )( a2 - ab + b2 )( a2 + ab + b2 )
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Method of Factorisation : the Sum Or Difference of Two Cubes
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