हिंदी
तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएसएसएलसी (अंग्रेजी माध्यम) कक्षा ९

Factorise the following polynomials using synthetic division: x3 – 10x2 – x + 10 - Mathematics

Advertisements
Advertisements

प्रश्न

Factorise the following polynomials using synthetic division:

x3 – 10x2 – x + 10

योग

उत्तर

p(x) = x3 – 10x2 – x + 10

= 1 – 10 – 1 + 10

= 11 – 11

= 0

∴ x – 1 is a factor

x2 – 9x – 10 = x2 – 10x + x – 10

= x(x – 10) + 1(x – 10)

= (x – 10)(x + 1)

This (x – 1)(x + 1)(x – 10) are the factors.

∴ x3 – 10x2 – x + 10 = (x – 1)(x – 10)(x + 1)

shaalaa.com
Synthetic Division
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Algebra - Exercise 3.8 [पृष्ठ ११४]

APPEARS IN

सामाचीर कलवी Mathematics [English] Class 9 TN Board
अध्याय 3 Algebra
Exercise 3.8 | Q 1. (vi) | पृष्ठ ११४
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×