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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 9

Factorise the following polynomials using synthetic division: x3 – 10x2 – x + 10 - Mathematics

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Question

Factorise the following polynomials using synthetic division:

x3 – 10x2 – x + 10

Sum

Solution

p(x) = x3 – 10x2 – x + 10

= 1 – 10 – 1 + 10

= 11 – 11

= 0

∴ x – 1 is a factor

x2 – 9x – 10 = x2 – 10x + x – 10

= x(x – 10) + 1(x – 10)

= (x – 10)(x + 1)

This (x – 1)(x + 1)(x – 10) are the factors.

∴ x3 – 10x2 – x + 10 = (x – 1)(x – 10)(x + 1)

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Synthetic Division
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Chapter 3: Algebra - Exercise 3.8 [Page 114]

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Samacheer Kalvi Mathematics [English] Class 9 TN Board
Chapter 3 Algebra
Exercise 3.8 | Q 1. (vi) | Page 114
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