Advertisements
Advertisements
प्रश्न
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
3a2b3 – 27a4b
उत्तर
We have,
3a2b3 – 27a4b = 3a2b(b2 – 9a2)
= 3a2b[b2 – (3a)2]
= 3a2b(b + 3a)(b – 3a)
APPEARS IN
संबंधित प्रश्न
Expand: 102 x 98
Factorise the following algebraic expression by using the identity a2 – b2 = (a + b)(a – b)
x4 – y4
Using suitable identities, evaluate the following.
9.8 × 10.2
Using suitable identities, evaluate the following.
(132)2 – (68)2
Factorise the expression and divide them as directed:
(x2 – 22x + 117) ÷ (x – 13)
Factorise the expression and divide them as directed:
(3x4 – 1875) ÷ (3x2 – 75)
The radius of a circle is 7ab – 7bc – 14ac. Find the circumference of the circle. `(pi = 22/7)`
Verify the following:
(ab + bc)(ab – bc) + (bc + ca)(bc – ca) + (ca + ab)(ca – ab) = 0
Find the value of a, if pq2a = (4pq + 3q)2 – (4pq – 3q)2
The product of two expressions is x5 + x3 + x. If one of them is x2 + x + 1, find the other.
