Advertisements
Advertisements
प्रश्न
Find all possible values of y for which distance between the points is 10 units.
उत्तर
The given points are A(2,-3) and B(10, y)
`∴AB = sqrt((2-10)^2 +(-3-y)^2)`
`=sqrt((-8)^2 + (-3-y)^2)`
`=sqrt(64+9+y^2+6y)`
∵ AB= 10
`∴sqrt(64+9+y^2+6y =10)`
`⇒ 73+y^2+6y =100` (Squaring both sides)
`⇒y^2+6y-27 = 0`
`⇒y^2+9y -3y-27=0`
`⇒ y(y+9)-3(y+9)=0`
`⇒(y+9)(y-3)=0`
⇒y+9=0 or y-3=0
⇒ y=-9 or y=3
Hence, the possible values of y are -9 and 3.
APPEARS IN
संबंधित प्रश्न
Find the distance between two points
(i) P(–6, 7) and Q(–1, –5)
(ii) R(a + b, a – b) and S(a – b, –a – b)
(iii) `A(at_1^2,2at_1)" and " B(at_2^2,2at_2)`
Show that four points (0, – 1), (6, 7), (–2, 3) and (8, 3) are the vertices of a rectangle. Also, find its area
Check whether (5, -2), (6, 4) and (7, -2) are the vertices of an isosceles triangle.
Find the distance between the following pairs of point.
W `((- 7)/2 , 4)`, X (11, 4)
Find the value of y for which the distance between the points A (3, −1) and B (11, y) is 10 units.
AB and AC are the two chords of a circle whose radius is r. If p and q are
the distance of chord AB and CD, from the centre respectively and if
AB = 2AC then proove that 4q2 = p2 + 3r2.
From the given number line, find d(A, B):
What point on the x-axis is equidistant from the points (7, 6) and (-3, 4)?
Calculate the distance between A (7, 3) and B on the x-axis whose abscissa is 11.
What type of a quadrilateral do the points A(2, –2), B(7, 3), C(11, –1) and D(6, –6) taken in that order, form?
