Advertisements
Advertisements
प्रश्न
Find the area of an equilateral triangle having each side 4 cm.
उत्तर
Area of an equilateral triangle having each side a cm is given by
`A=sqrt(3)/4a^2`
Area of the given equilateral triangle having each equal side equal to 4 cm is given by
a = 4 cm
`A= sqrt(3)/4 (4)^2`
`A=sqrt(3)/4 xx 16`
`A = 4 sqrt(3) cm^2`
APPEARS IN
संबंधित प्रश्न
A field is in the shape of a trapezium whose parallel sides are 25 m and 10 m. The non-parallel sides are 14 m and 13 m. Find the area of the field.
Find the area of an equilateral triangle having altitude h cm.
The sides of a triangular field are 325 m, 300 m and 125 m. Its area is
The sides of a triangle are 11 cm, 15 cm and 16 cm. The altitude to the largest side is
Find the area of a quadrilateral ABCD whose sides are AB = 13 cm, BC = 12 cm, CD = 9 cm, AD = 14 cm and diagonal BD = 15 cm
The sides of a triangle are 56 cm, 60 cm and 52 cm long. Then the area of the triangle is ______.
The area of an equilateral triangle with side `2sqrt(3)` cm is ______.
The sides of a triangle are 35 cm, 54 cm and 61 cm, respectively. The length of its longest altitude ______.
The area of an isosceles triangle having base 2 cm and the length of one of the equal sides 4 cm, is ______.
The area of a regular hexagon of side ‘a’ is the sum of the areas of the five equilateral triangles with side a.