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प्रश्न
Find the area and perimeter of the following sector :
Radius= 4.2 cm, angle at the centre is 60 °
उत्तर
Area of the sector = `(pi "r"^2 xx theta/360^circ)`
`= 22/7 xx 4.2 xx 4.2 xx 60^circ/360^circ`
= 9.24 cm2
Peri meter of the sector
= 2r + `(2 pi "r" xx theta/360^circ)`
`=2 xx 4.2 + (2 xx 22/7 xx 4.2 xx 60^circ/360^circ)`
= 8.4 + 4.4
= 12.8 cm
Area of the sector = 9.24 cm2 and perimeter = 12.8 cm
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