Advertisements
Advertisements
प्रश्न
Find the nature of roots of the following quadratic equations:
` 3x^2-2sqrt6x+2=0`
उत्तर
The given equation is `3x^2-2sqrt6x+2=0`
This is of the form `ax^2+bx+c=0` where `a=2, b=-8 and c=5`
∴ Discriminant, `D=b^2-4ac=(-2sqrt6)^2-4xx3xx2=24-24=0`
Hence, the given equation has real and equal roots.
APPEARS IN
संबंधित प्रश्न
` 2x^2-7x+6=0`
`(x-1)(2x-1)=0`
`11-x=2x^2`
Find the roots of the each of the following equations, if they exist, by applying the quadratic formula:
`x^2-4x-1=0`
`x^2-(sqrt3+1)x+sqrt3=0`
`x-1/x=3,x≠0`
For what value of k are the roots of the quadratic equation `kx(x-2sqrt5)+10=0`real and equal.
If -5 is a root of the quadratic equation `2x^2+px-15=0` and the quadratic equation `p(x^2+x)+k=0` 0has equal roots, find the value of k.
A two-digit number is such that the product of its digits is 14. If 45 is added to the number, the digit interchange their places. Find the number.
The denominator of a fraction is 3 more than its numerator. The sum of the fraction and its reciprocal is `2 9/10` Find the fraction.
