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Find p and q, if the following equation represents a pair of perpendicular lines6x2 + 5xy – py2 + 7x + qy – 5 = 0 - Mathematics

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प्रश्न

Find p and q, if the following equation represents a pair of perpendicular lines
6x2 + 5xy – py2 + 7x + qy – 5 = 0

योग

उत्तर

The equation of the given pair of straight lines is

6x2 + 5xy – py2 + 7x + qy – 5 = 0    ......(1)

Given that equation (1) represents a pair of perpendicular straight lines.

∴ Coefficient of x2 + coefficient of y2 = 0

6 – p = 0

⇒ p = 6

6x2 + 5xy – 6y2 = 6x2 + 9xy – 4xy – 6y2

= 3x(2x + 3y) – 2y (2x + 3y)

= (2x + 3y)(3x – 2y)

Let the separate equation of the straight lines be

2x + 3y + 1 = 0 and 3x – 2y + m = 0

6x2 + 5xy – 6y2 + 7x + qy – 5

= (2x + 3y + 1)(3x – 2y + m)

Comparing the coefficients of x, y and constant terms on both sides

2m + 3l = 7   ......(2)

3m – 2l = q   ......(3)

lm = – 5   ......(4)

Equation (4)

⇒ l = 1

m = – 5

or

l = – 1

m = 5

When l = 1

m = – 5 ,

Equation (2) does not satisfy.

∴ l = – 1 

m = 5

Substituting in equation (3)

3(5) – 2(–1) = q

⇒ q = 17

∴ The required values are p = 6, q = 17

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Pair of Straight Lines
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Two Dimensional Analytical Geometry - Exercise 6.4 [पृष्ठ २८२]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 6 Two Dimensional Analytical Geometry
Exercise 6.4 | Q 11 | पृष्ठ २८२

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