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Find the equation of the ellipse with foci at (± 5, 0) and x = 365 as one of the directrices. - Mathematics

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प्रश्न

Find the equation of the ellipse with foci at (± 5, 0) and x = `36/5` as one of the directrices.

योग

उत्तर

We have ae = 5, `a/e = 36/5`

Which give a 2 = 36 or a = 6

Therefore, e = `5/6`.

Now `b = asqrt(1 - "e"^2)`

= `6sqrt(1 - 25/36)`

= `sqrt(11)`.

Thus, the equation of the ellipse is `x^2/36 + y^2/11` = 1.

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अध्याय 11: Conic Sections - Solved Examples [पृष्ठ १९४]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 11 Conic Sections
Solved Examples | Q 4 | पृष्ठ १९४

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