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Find the equations of the line through (1, 3) and making an intercept of 5 on the y-axis. - Mathematics

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प्रश्न

Find the equations of the line through (1, 3) and making an intercept of 5 on the y-axis.

योग

उत्तर

Since, y-intercept = 5, so the corresponding point on y-axis is (0, 5).

The line passes through (1, 3).

∴ Slope of the line = `(5 - 3)/(0 - 1) = 2/(-1) = -2`

Required equation of the line is given by:

y − y1 = m(x − x1)

y − 5 = −2(x − 0)

y − 5 = −2x

2x + y = 5

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Equation of a Line
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 14: Equation of a Line - Exercise 14 (C) [पृष्ठ १९७]

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सेलिना Mathematics [English] Class 10 ICSE
अध्याय 14 Equation of a Line
Exercise 14 (C) | Q 18 | पृष्ठ १९७
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