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प्रश्न
Find the equation of the line with x-intercept 5 and a point on it (–3, 2).
उत्तर
Since, x-intercept is 5, so the corresponding point on x-axis is (5, 0).
The line also passes through (–3, 2).
∴ Slope of the line = `(2 - 0)/(-3 - 5) = 2/-8 = (-1)/4`
Required equation of the line is given by:
y – y1 = m(x – x1)
`y - 0 = (-1)/4 (x - 5)`
4y = –x + 5
x + 4y = 5
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