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प्रश्न
Find the number of sides in a regular polygon, if its interior angle is: 150°
उत्तर
Let no.of.sides of regular polygon be n.
Each interior angle = 150°
`therefore (("2n" - 4) xx 90^circ)/"n" = 150^circ`
180n - 360° = 150n
180n - 150n = 360°
30n = 360°
n = 12
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संबंधित प्रश्न
Fill in the blanks :
In case of regular polygon, with :
| No.of.sides | Each exterior angle | Each interior angle |
| (i) ___8___ | _______ | ______ |
| (ii) ___12____ | _______ | ______ |
| (iii) _________ | _____72°_____ | ______ |
| (iv) _________ | _____45°_____ | ______ |
| (v) _________ | __________ | _____150°_____ |
| (vi) ________ | __________ | ______140°____ |
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AB, BC and CD are three consecutive sides of a regular polygon. If angle BAC = 20° ; find :
(i) its each interior angle,
(ii) its each exterior angle
(iii) the number of sides in the polygon.
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(i) ∠BAE
(ii) ∠ABE
(iii) ∠BED
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Is it possible to have a regular polygon whose interior angle is: 155°
