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प्रश्न
Find the points on the curve y = (cosx – 1) in [0, 2π], where the tangent is parallel to x-axis
उत्तर
We have y = cosx – 1
∴ `"dy"/"dx"` = – sin x
For tangent to be parallel to x-axis
We must have `"dy"/"dx"` = 0
∴ – sin x = 0
∴ x = π ∈ [0, 2π]
y(π) = cos π – 1 = –2
Hence, the required point on the curve, where the tangent drawn is parallel to the x-axis is (π, –2)
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