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प्रश्न
Give the equations of two lines passing through (2, 14). How many more such lines are there, and why?
उत्तर
It can be observed that point (2, 14) satisfies the equation 7x − y = 0 and x − y + 12 = 0.
Therefore, 7x − y = 0 and x − y + 12 = 0 are two lines passing through point (2, 14).
As it is known that through one point, infinite number of lines can pass through, therefore, there are infinite lines of such type passing through the given point.
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संबंधित प्रश्न
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Draw the graph for the equation, given below :
y + 7 = 0
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From the graph, find:
(i) x1, the value of x, when y = 7
(ii) x2, the value of x, when y = - 5.
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By drawing a graph for each of the equations 3x + y + 5 = 0; 3y - x = 5 and 2x + 5y = 1 on the same graph paper; show that the lines given by these equations are concurrent (i.e. they pass through the same point). Take 2 cm = 1 unit on both the axes.
Draw the graph for the following
y = 2x
Draw the graph for the following
y = 4x – 1
Draw the graph of the following equation:
x = – 7
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