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प्रश्न
How many isomers of the following hydrocharbons are possible?
C3H8
उत्तर
C3H8 doesn't have isomers, as isomerism is only possible if the number of carbon atoms is 4 or more
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- \[\begin{array}{cc}
\ce{CH3}\phantom{.....}\ce{CH3}\phantom{.........}\ce{CH3}\phantom{..}\ce{CH3}\phantom{..........}\\
\phantom{...}\backslash\phantom{......}/\phantom{................}|\phantom{.....}|\phantom{............}\\
\ce{C} = \ce{C} + \ce{H2} \overset{\ce{Ni}}{\rightarrow} \ce{CH3 - C - C - CH3}\\
\phantom{.}/\phantom{........}\backslash\phantom{..............}|\phantom{....}|\phantom{.........}\\
\ce{CH3}\phantom{....}\ce{CH3}\phantom{............}\ce{H}\phantom{...}\ce{H}\phantom{........}
\end{array}\] - \[\ce{CH3COOH + CH3CH2OH \overset{\ce{Conc. H2SO4}}{\rightarrow}CH3COOC2H5 + H2O}\]
- \[\ce{CH3CH2OH}\ce{->[Alk.KMnO4][Heat]CH3COOH}\]