Advertisements
Advertisements
प्रश्न
If 1is a zero of the quadratic polynomial `ax^2 – 3(a – 1)x – 1`is 1, then find the value of a.
उत्तर
Given: x = 1 is one zero of the polynomial `ax^2 – 3(a – 1) x – 1`
Therefore, it will satisfy the above polynomial.
Now, we have
`a(1)^2 – (a – 1)1 – 1 = 0`
`⇒ a – 3a + 3 – 1 = 0`
`⇒ –2a = – 2`
`⇒ a = 1`
APPEARS IN
संबंधित प्रश्न
If f(x) =`x^3-3x+5x-3` is divided by g(x)=`x^2-2`
Find all the zeroes of polynomial `(2x^4 – 11x^3 + 7x^2 + 13x – 7)`, it being given that two of its zeroes are `(3 + sqrt2) and (3 – sqrt2)`.
Find the sum of the zeros and the product of zeros of a quadratic polynomial, are `−1/2` and \ -3 respectively. Write the polynomial.
A quadratic polynomial, whose zeroes are -3 and 4, is ______.
The zeroes of the quadratic polynomial x2 + 99x + 127 are ______.
If p(x) is a polynomial of at least degree one and p(k) = 0, then k is known as ______.
If one of the zeroes of the quadratic polynomial (k -1)x² + kx + 1 the value of k is ______.
If 4x² – 6x – m is divisible by x – 3, the value of m is exact divisor of ______.
The zeroes of the polynomial 3x2 + 11x – 4 are ______.
The zeroes of the quadratic polynomial 16x2 – 9 are ______.
