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Question
If 1is a zero of the quadratic polynomial `ax^2 – 3(a – 1)x – 1`is 1, then find the value of a.
Solution
Given: x = 1 is one zero of the polynomial `ax^2 – 3(a – 1) x – 1`
Therefore, it will satisfy the above polynomial.
Now, we have
`a(1)^2 – (a – 1)1 – 1 = 0`
`⇒ a – 3a + 3 – 1 = 0`
`⇒ –2a = – 2`
`⇒ a = 1`
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