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तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएसएसएलसी (अंग्रेजी माध्यम) कक्षा १०

If A = [43123-810-4], B = [234192-71-1] and C = [8341-2324-1] then verify that A + (B + C) = (A + B) + C - Mathematics

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प्रश्न

If A = `[(4, 3, 1),(2, 3, -8),(1, 0, -4)]`, B = `[(2, 3, 4),(1, 9, 2),(-7, 1, -1)]` and C = `[(8, 3, 4),(1, -2, 3),(2, 4, -1)]` then verify that A + (B + C) = (A + B) + C

योग

उत्तर

B + C = `[(2, 3, 4),(1, 9, 2),(-7, 1, -1)] + [(8, 3, 4),(1, -2, 3),(2, 4, -1)]` 

= `[(10, 6, 8),(2, 7, 5),(-5, 5, -2)]`

A + (B + C) = `[(4, 3, 1),(2, 3, -8),(1, 0, -4)] + [(10, 6, 8),(2, 7, 5),(-5, 5, -2)]`

= `[(14, 9, 9),(4, 10, -3),(-4, 5, -6)]`  ....(1)

(A + B) = `[(4, 3, 1),(2, 3, 8),(1, 0, 4)] + [(2, 3, 4),(1, 9, 2),(-7, 1, -1)]`

= `[(6, 6, 5),(3, 12, -6),(-6, 1, -5)]`

(A + B) + C = `[(6, 6, 5),(3, 12, -6),(-6, 1, -5)] + [(8, 3, 4),(1, -2, 3),(2, 4, -1)]`

= `[(14, 9, 9),(4, 10, -3),(-4, 5, -6)]`   ....(2)

From (1) and (2) we get

A + (B + C) = (A + B) + C

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अध्याय 3: Algebra - Exercise 3.17 [पृष्ठ १४८]

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सामाचीर कलवी Mathematics [English] Class 10 SSLC TN Board
अध्याय 3 Algebra
Exercise 3.17 | Q 2 | पृष्ठ १४८
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