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If A, B, C, D are angles of a cyclic quadrilateral, prove that: cos A + cos B + cos C + cos D = 0. - Business Mathematics and Statistics

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प्रश्न

If A, B, C, D are angles of a cyclic quadrilateral, prove that: cos A + cos B + cos C + cos D = 0.

योग

उत्तर

In a cyclic quadrilateral sum of opposite angles are 180°.

Since A, B, C, D are angles of cyclic quadrilateral

A + C = 180° and B + D = 180°

LHS = cos A + cos B + cos C + cos D

= cos A + cos B + cos(180° – A) + cos(180° – B)

= cos A + cos B – cos A – cos B

= 0

= RHS

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Trigonometric Ratios
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Trigonometry - Exercise 4.1 [पृष्ठ ८१]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 11 TN Board
अध्याय 4 Trigonometry
Exercise 4.1 | Q 6 | पृष्ठ ८१
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