Advertisements
Advertisements
प्रश्न
If log 2 = 0.3010 and log 3 = 0.4771 ; find the value of : log 12
उत्तर
We know that log 2 = 0.3010 and log 3 = 0.4771
log 12
= log 2 x 2 x 3
= log 2 x 2 + log 3 ...[ logamn = logam + logan ]
= log22 + log3
= 2log2 + log 3 ...[ nlogam = logamn ]
= 2( 0.3010 ) + 0.4771 ...[ ∵ log 2 = 0.3010 and log3 = 0.4771 ]
= 1.0791
APPEARS IN
संबंधित प्रश्न
If log (a + b) = log a + log b, find a in terms of b.
If log10 8 = 0.90; find the value of : log 0.125
Prove that : (log a)2 - (log b)2 = log `(( a )/( b ))` . Log (ab)
Given log x = 2m - n , log y = n - 2m and log z = 3m - 2n , find in terms of m and n, the value of log `(x^2y^3 ) /(z^4) `.
Express the following in terms of log 5 and/or log 2: log125
Express the following in terms of log 2 and log 3: `"log"root(5)(216)`
Express the following as a single logarithm:
log 18 + log 25 - log 30
If log 2 = 0.3010, log 3 = 0.4771 and log 5 = 0.6990, find the values of: log18
If log 8 = 0.90, find the value of each of the following: `"log"sqrt(32)`
If log 27 = 1.431, find the value of the following: log300
