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If tan–1x + tan–1y + tan–1z = π, show that x + y + z = xyz - Mathematics

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प्रश्न

If tan–1x + tan1y + tan1z = π, show that x + y + z = xyz

योग

उत्तर

tan–1x + tan1y + tan1z = π

`tan^-1 [(x + y)/(1 - xy)] + tan^-1z = pi`

`tan^-1  [((x + y)/(1 - xy) + z)/(1 - ((x + y)/(1 - xy))z)] = pi`

`tan^-1 [((x + y + z(1 - xy))/(1 - xy))/((1 - xy - (xz + yz))/(1 - xy))] = pi`

`(x + y + z - zyz)/(1 - xy - xz - yz) = tanpi` = 0

x + y + z – xyz = 0

x + y + z = xyz

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अध्याय 4: Inverse Trigonometric Functions - Exercise 4.5 [पृष्ठ १६६]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 4 Inverse Trigonometric Functions
Exercise 4.5 | Q 6 | पृष्ठ १६६

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