Advertisements
Advertisements
प्रश्न
If the distance between point L(x, 7) and point M(1, 15) is 10, then find the value of x
उत्तर
Let L(x1, y1) = L(x, 7) and M (x2, y2) = M(1, 15)
x1 = x, y1 = 7, x2 = 1, y2 = 15
By distance formula,
d(L, M) = `sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2`
∴ d(L, M) = `sqrt((1 - x)^2 + (15 - 7)^2`
∴ 10 = `sqrt((1 - x)^2 + 8^2`
∴ 100 = (1 – x)2 + 64 ......[Squaring both sides]
∴ (1 – x)2 = 100 – 64
∴ (1 – x)2 = 36
∴ 1 – x = `+- sqrt(36)` .....[Taking square root of both sides]
∴ 1 – x = ± 6
∴ 1 – x = 6 or 1 – x = – 6
∴ x = – 5 or x = 7
∴ The value of x is – 5 or 7.
APPEARS IN
संबंधित प्रश्न
Find the value of x, if the distance between the points (x, – 1) and (3, 2) is 5.
Name the type of quadrilateral formed, if any, by the following point, and give reasons for your answer:
(−3, 5), (3, 1), (0, 3), (−1, −4)
Find all possible values of y for which distance between the points is 10 units.
Find the distances between the following point.
R(–3a, a), S(a, –2a)
Find the value of y for which the distance between the points A (3, −1) and B (11, y) is 10 units.
Find the distance between the following point :
(sec θ , tan θ) and (- tan θ , sec θ)
Prove that the following set of point is collinear :
(4, -5),(1 , 1),(-2 , 7)
Prove that the points (0 , 2) , (1 , 1) , (4 , 4) and (3 , 5) are the vertices of a rectangle.
A point A is at a distance of `sqrt(10)` unit from the point (4, 3). Find the co-ordinates of point A, if its ordinate is twice its abscissa.
Points A (-3, -2), B (-6, a), C (-3, -4) and D (0, -1) are the vertices of quadrilateral ABCD; find a if 'a' is negative and AB = CD.
The distances of point P (x, y) from the points A (1, - 3) and B (- 2, 2) are in the ratio 2: 3.
Show that: 5x2 + 5y2 - 34x + 70y + 58 = 0.
Find the distance of the following points from origin.
(a+b, a-b)
Use distance formula to show that the points A(-1, 2), B(2, 5) and C(-5, -2) are collinear.
Find distance of point A(6, 8) from origin
The coordinates of the point which is equidistant from the three vertices of the ΔAOB as shown in the figure is ______.
The distance between the point P(1, 4) and Q(4, 0) is ______.
∆ABC with vertices A(–2, 0), B(2, 0) and C(0, 2) is similar to ∆DEF with vertices D(–4, 0), E(4, 0) and F(0, 4).
Ayush starts walking from his house to office. Instead of going to the office directly, he goes to a bank first, from there to his daughter’s school and then reaches the office. What is the extra distance travelled by Ayush in reaching his office? (Assume that all distances covered are in straight lines). If the house is situated at (2, 4), bank at (5, 8), school at (13, 14) and office at (13, 26) and coordinates are in km.
If (a, b) is the mid-point of the line segment joining the points A(10, –6) and B(k, 4) and a – 2b = 18, find the value of k and the distance AB.
Case Study Trigonometry in the form of triangulation forms the basis of navigation, whether it is by land, sea or air. GPS a radio navigation system helps to locate our position on earth with the help of satellites. |
- Make a labelled figure on the basis of the given information and calculate the distance of the boat from the foot of the observation tower.
- After 10 minutes, the guard observed that the boat was approaching the tower and its distance from tower is reduced by 240(`sqrt(3)` - 1) m. He immediately raised the alarm. What was the new angle of depression of the boat from the top of the observation tower?