Advertisements
Advertisements
प्रश्न
If (x – 1) divides the polynomial kx3 – 2x2 + 25x – 26 without remainder, then find the value of k
उत्तर
p(x) = kx3 – 2x2 + 25x – 26
When it is divided by x – 1
P(1) = 0
k(1)3 – 2(1)2 + 25(1) – 26 = 0
k – 2 + 25 – 26 = 0
k + 25 – 28 = 0
k – 3 = 0
k = 3
The value of k = 3
APPEARS IN
संबंधित प्रश्न
Show that 3x + 2 is a factor of 3x2 – x – 2.
Show that m − 1 is a factor of m21 − 1 and m22 − 1.
Prove by factor theorem that
(3x-2) is a factor of 18x3 - 3x2 + 6x -12
Prove by factor theorem that
(2x - 1) is a factor of 6x3 - x2 - 5x +2
Prove that ( p-q) is a factor of (q - r)3 + (r - p) 3
Using factor theorem, show that (x - 3) is a factor of x3 - 7x2 + 15x - 9, Hence, factorise the given expression completely.
Using the Remainder and Factor Theorem, factorise the following polynomial: x3 + 10x2 – 37x + 26.
Determine whether (x – 1) is a factor of the following polynomials:
x3 + 5x2 – 10x + 4
If x – 3 is a factor of p(x), then the remainder is
Find the value of 'a' if x – a is a factor of the polynomial 3x3 + x2 – ax – 81.