Advertisements
Advertisements
प्रश्न
In a flight of 600 km, an aircraft was slowed due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of the flight increased by 30 minutes. Find the scheduled duration of the flight.
उत्तर
Let the normal Speed of the aircraft be S, and time taken be t.
Distance = 600 km
Time = `"Distance"/"Speed"`
Hence , t = `600/S` ......(i)
And t + 0.5 = `600/(S - 200)` ......(ii)
Puttiing (i) in (ii), we get
`600/(S - 200) - 1/2 = 600/S`
⇒ `(1200 - S + 200)/(2 S - 400) = 600/"S"`
⇒ 1200 S – S2 + 200 S = 1200 S – 2400000
⇒ S2 – 200 S – 240000 = 0
⇒ S2 – 600 S + 400 S – 240000 = 0
⇒ S (S – 600) + 400 (S – 600) = 0
⇒ (S – 600) (S + 400) = 0
Hence, S = 600 km/hr
⇒ T = `600/600` = 1 Hour
संबंधित प्रश्न
`sqrt3x^2+10x+7sqrt3=0`
By using the method of completing the square, show that the equation `2x^2+x+4=0` has no real roots.
Solve the following quadratic equation by completing the square method.
9y2 – 12y + 2 = 0
Fill in the gaps and complete.
Fill in the gap and complete.
Find the value of discriminant.
`sqrt2x^2 + 4x + 2sqrt2 = 0`
Form the quadratic equation from the roots given below.
\[\frac{1}{2}, - \frac{1}{2}\]
If p2x2 – q2 = 0, then x =?
The ratio of two numbers is 3:2 and the difference of their square is 500. Find the numbers.
Find the value of x, if `(4/7)^x (7/4)^(2x) = 343/64`.