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Question
In a flight of 600 km, an aircraft was slowed due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of the flight increased by 30 minutes. Find the scheduled duration of the flight.
Solution
Let the normal Speed of the aircraft be S, and time taken be t.
Distance = 600 km
Time = `"Distance"/"Speed"`
Hence , t = `600/S` ......(i)
And t + 0.5 = `600/(S - 200)` ......(ii)
Puttiing (i) in (ii), we get
`600/(S - 200) - 1/2 = 600/S`
⇒ `(1200 - S + 200)/(2 S - 400) = 600/"S"`
⇒ 1200 S – S2 + 200 S = 1200 S – 2400000
⇒ S2 – 200 S – 240000 = 0
⇒ S2 – 600 S + 400 S – 240000 = 0
⇒ S (S – 600) + 400 (S – 600) = 0
⇒ (S – 600) (S + 400) = 0
Hence, S = 600 km/hr
⇒ T = `600/600` = 1 Hour
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