Advertisements
Advertisements
प्रश्न
In a flight of 600 km, an aircraft was slowed due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of the flight increased by 30 minutes. Find the scheduled duration of the flight.
उत्तर
Let the normal Speed of the aircraft be S, and time taken be t.
Distance = 600 km
Time = `"Distance"/"Speed"`
Hence , t = `600/S` ......(i)
And t + 0.5 = `600/(S - 200)` ......(ii)
Puttiing (i) in (ii), we get
`600/(S - 200) - 1/2 = 600/S`
⇒ `(1200 - S + 200)/(2 S - 400) = 600/"S"`
⇒ 1200 S – S2 + 200 S = 1200 S – 2400000
⇒ S2 – 200 S – 240000 = 0
⇒ S2 – 600 S + 400 S – 240000 = 0
⇒ S (S – 600) + 400 (S – 600) = 0
⇒ (S – 600) (S + 400) = 0
Hence, S = 600 km/hr
⇒ T = `600/600` = 1 Hour
संबंधित प्रश्न
Two water taps together can fill a tank in `9 3/8`hours. The tap of larger diameter takes 10 hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank.
The sum of the areas of two squares is `640m^2` . If the difference in their perimeter be 64m, find the sides of the two square
The hypotenuse of a right=-angled triangle is 20 meters. If the difference between the lengths of the other sides be 4 meters, find the other sides
α, β are roots of y2 – 2y –7 = 0 find,
α2 + β2
α, β are roots of y2 – 2y –7 = 0 find,
α3 + β3
To fill a swimming pool two pipes are used. If the pipe of larger diameter used for 4 hours and the pipe of smaller diameter for 9 hours, only half of the pool can be filled. Find, how long it would take for each pipe to fill the pool separately, if the pipe of smaller diameter takes 10 hours more than the pipe of larger diameter to fill the pool?
The value of \[\sqrt{6 + \sqrt{6 + \sqrt{6 +}}} . . . .\] is
Complete the following activity to solve the given word problem. The Sum of squares of two consecutive even natural numbers is 244, then find those numbers.
Activity: Let the first even natural number be x
Therefore its consecutive even natural number will be = (______)
By the given condition,
x2 + (x + 2)2 = 244
x2 + x2 + 4x + 4 – (______) = 0
2x2 + 4x – 240 = 0
x2 + 2x – 120 = 0
x2 + (______) – (______) – 120 = 0
x(x + 12) – (______) (x + 12) = 0
(x + 12)(x – 10) = 0
x = (______)/x = 10
But natural number cannot be negative, x = – 12 is not possible.
Therefore first even natural number is x = 10.
Second even consecutive natural number = x + 2 = 10 + 2 = 12.
The value of `sqrt(6 + sqrt(6 + sqrt(6 ....)))`
Find the remainder when p(x) = 3x2 + 2x – 7 is divided by 2x + 1.
