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In an AP, given a = 7, a13 = 35, find d and S13. - Mathematics

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प्रश्न

In an AP, given a = 7, a13 = 35, find d and S13.

In an A.P. (with usual notations): given a = 7, a13 = 35, find d and S13.

योग

उत्तर

Given that, a = 7, a13 = 35

As an = a + (n − 1) d,

∴ a13 = a + (13 − 1) d

35 = 7 + 12d

35 − 7 = 12d

28 = 12d

d = `28/12`

d = `7/3`

sn = `n/2[a+a_n]`

S13 = `n/2[a+a_13]`

= `13/2[7+35]`

= `(13xx42)/2`

= 13 × 21

= 273

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अध्याय 5: Arithmetic Progressions - Exercise 5.3 [पृष्ठ ११२]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 10
अध्याय 5 Arithmetic Progressions
Exercise 5.3 | Q 3.02 | पृष्ठ ११२
एमएल अग्रवाल Understanding ICSE Mathematics [English] Class 10
अध्याय 9 Arithmetic and Geometric Progressions
Exercise 9.3 | Q 4.2

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