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प्रश्न
In the given figure ABCD is a rectangle. It consists of a circle and two semi-circles each of
which are of radius 5 cm. Find the area of the shaded region. Give your answer correct to
three significant figures
उत्तर
Length of a rectangle = Radius of two semi-circles Diameter of a circle
= 5 + 5 + 10
= 20 cm
Breadth of a rectangle = Diameter of a circle = 2 x 5 = 10 cm
∴ Area of a rectangle = Length x Breadth
= 20 x 10
= 200 sq. cm
Area of circle = `22/7 xx 5 xx 5` = 78.571 sq.cm
And, area of two semi-circles each of radius 5 cm = `2(1/2 xx 78.571)` = 78.571 sq. cm
Now,
Area of shaded region = Area of a rectangle - Area of a circle - Area of two semi- circle
= 200 - 78.571 - 78.571
= 200 - 157.142
= 42.858 sq.cm
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संबंधित प्रश्न
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1) the coordinate of the fourth vertex D
2) length of diagonal BD
3) equation of the side AD of the parallelogram ABCD
Using a graph paper, plot the points A(6, 4) and B(0, 4).
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- Write the co-ordinates of A' and B'.
- State the geometrical name for the figure ABA'B'.
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(1, 5) and (–3, –1) are the co-ordinates of vertices A and C respectively of rhombus ABCD. Find the equations of the diagonals AC and BD.
A line through origin meets the line x = 3y + 2 at right angles at point X. Find the co-ordinates of X.
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- the co-ordinates of A and B.
- equation of line through P and perpendicular to AB.
Point A and B have co-ordinates (7, −3) and (1, 9) respectively. Find:
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- the equation of perpendicular bisector of the line segment AB.
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Use a graph sheet for this question.
Take 1 cm = 1 unit along both x and y axis.
(i) Plot the following points:
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Use a graph sheet for this question, take 2 cm = 1 unit along both x and y-axis:
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- Name the closed figure A’B’AB.