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प्रश्न
In the given figure, the shape of the top of a table is that of a sector of a circle with centre O and ∠AOB = 90°. If AO = OB = 42 cm,· then find the perimeter of the top of the table.
उत्तर
We have
r = 42 cm and θ = 360° - 90° = 270°
Perimeter of the top of the table = Length of the major arc AB + Length of OA + Length of OB
`=theta/360^circxx2pir+42+42`
`=270^circ/360^circxx2xx22/7xx42+84`
`=198 + 84`
= 282 cm
Hence, the perimeter of the top of the table is 282 cm.
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