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In the Seating Arrangement of Desks in a Classroom Three Students Rohini, Sandhya and Bina Are Seated at A(3, 1), B(6, 4), and C(8, 6). Do You Think They Are Seated in a Line? - Mathematics

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प्रश्न

In the seating arrangement of desks in a classroom three students Rohini, Sandhya and Bina are seated at A(3, 1), B(6, 4), and C(8, 6). Do you think they are seated in a line?

उत्तर

The distance d between two points `(x_1, y_1)` and `(x_2, y_2)` is given by the formula

`d = sqrt((x_1 -  x_2)^2 + (y_1 -y_2)^2)`

For three points to be collinear the sum of distances between any two pairs of points should be equal to the third pair of points.

The given points are A(3,1), B(6,4)\ and C(8,6).

Let us find the distances between the possible pairs of points.

`AB = sqrt((3 - 6)^2 + (1 - 4)^2)`

`= sqrt((-3)^2 + (-3)^2)`

`= sqrt(9 + 9)`

`AB = 3sqrt2`

`AC = sqrt((3 - 8)^2 + (1 - 6)^2)`

`= sqrt((-5)^2 +(-5)^2)`

`= sqrt(25 + 25)`

`AC = 5sqrt2`

`BC = sqrt((6 - 8)^2 + (4 - 6)^2)`

`= sqrt((-2)^2 + (-2)^2)`

`= sqrt(4 = 4)`

`BC= 2sqrt2`

We see that AB + BC = AC

Since sum of distances between two pairs of points equals the distance between the third pair of points the three points must be collinear.

Hence, the three given points are collinear.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Co-Ordinate Geometry - Exercise 6.2 [पृष्ठ १७]

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आरडी शर्मा Mathematics [English] Class 10
अध्याय 6 Co-Ordinate Geometry
Exercise 6.2 | Q 41 | पृष्ठ १७

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