Advertisements
Advertisements
प्रश्न
In the following two polynomials. Find the value of ‘a’ if x + a is a factor of each of the two:
x3 + ax2 - 2x + a + 4
उत्तर
Let p(x) = x3 + ax2 - 2x + a + 4 ...(i)
Since, (x + a) is a factor of p(x), so p(-a) = 0
Put x = -a in equation (i), we get
p(-a) = (-a)3 + a(-a)2 -2(-a) + a + 4
= -a3 + a(a2) + 2a + a + 4
= -a3 + a3 + 3a + 4
= 3a + 4
But p(-a) = 0
⇒ 3a + 4 = 0
⇒ 3a = -4
⇒ a = `-(4)/(3)`.
APPEARS IN
संबंधित प्रश्न
A two digit positive number is such that the product of its digits is 6. If 9 is added to the number, the digits interchange their places. Find the number.
When divided by x – 3 the polynomials x3 – px2 + x + 6 and 2x3 – x2 – (p + 3) x – 6 leave the same remainder. Find the value of ‘p’.
Factorise the expression f(x) = 2x3 – 7x2 – 3x + 18. Hence, find all possible values of x for which f(x) = 0.
Show that (x – 1) is a factor of x3 – 7x2 + 14x – 8. Hence, completely factorise the given expression.
Find the values of a and b in the polynomial f(x) = 2x3 + ax2 + bx + 10, if it is exactly divisible by (x+2) and (2x-1).
Find the value of a and b so that the polynomial x3 - ax2 - 13x + b has (x - 1) (x + 3) as factor.
If x – 2 is a factor of each of the following three polynomials. Find the value of ‘a’ in each case:
x2 - 3x + 5a
When 3x2 – 5x + p is divided by (x – 2), the remainder is 3. Find the value of p. Also factorise the polynomial 3x2 – 5x + p – 3.
If (x + 3) and (x – 4) are factors of x3 + ax2 – bx + 24, find the values of a and b: With these values of a and b, factorise the given expression.
One factor of x3 – kx2 + 11x – 6 is x – 1. The value of k is ______.