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प्रश्न
In the given figure, AOB is a straight line. Find the value of x and also answer each of the following:
(i) ∠AOP = ……..
(ii) ∠BOP = ……..
(iii) which angle is obtuse?
(iv) which angle is acute?
उत्तर
∠AOP = x + 30°
∠BOP = x – 30°
But ∠AOP + ∠BOP = 180° (∵ ∠AOB is a straight angle)
⇒ x + 30°+x - 30° = 180°
⇒ 2x = 180°
⇒ x = 90°
(i) ∠AOP = x + 30° = 90° + 30° = 120°.
(ii) ∠BOP = x- 30° = 90° – 30° = 60°.
(iii) ∠AOP is an obtuse angle.
(iv) ∠BOP is an acute angle.
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संबंधित प्रश्न
In the given figure:
(i) If ∠AOB = 45°, ∠BOC = 30° and ∠AOD= 110°; find : angles COD and BOD.
(ii) If ∠BOC = ∠DOC = 34° and ∠AOD = 120° ; find : angle AOB and angle AOC.
(iii) If ∠AOB = ∠BOC = ∠COD = 38° find : reflex angle AOC and reflex angle AOD.
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